10(x^2)+10(4x)+10(4)=40x+80

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Solution for 10(x^2)+10(4x)+10(4)=40x+80 equation: 


Simplifying
10(x2) + 10(4x) + 10(4) = 40x + 80

Remove parenthesis around (4x)
10x2 + 10 * 4x + 10(4) = 40x + 80

Multiply 10 * 4
10x2 + 40x + 10(4) = 40x + 80

Multiply 10 * 4
10x2 + 40x + 40 = 40x + 80

Reorder the terms:
40 + 40x + 10x2 = 40x + 80

Reorder the terms:
40 + 40x + 10x2 = 80 + 40x

Add '-40x' to each side of the equation.
40 + 40x + -40x + 10x2 = 80 + 40x + -40x

Combine like terms: 40x + -40x = 0
40 + 0 + 10x2 = 80 + 40x + -40x
40 + 10x2 = 80 + 40x + -40x

Combine like terms: 40x + -40x = 0
40 + 10x2 = 80 + 0
40 + 10x2 = 80

Solving
40 + 10x2 = 80

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + 10x2 = 80 + -40

Combine like terms: 40 + -40 = 0
0 + 10x2 = 80 + -40
10x2 = 80 + -40

Combine like terms: 80 + -40 = 40
10x2 = 40

Divide each side by '10'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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